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24.5x-4.9x^2+29.4=0
a = -4.9; b = 24.5; c = +29.4;
Δ = b2-4ac
Δ = 24.52-4·(-4.9)·29.4
Δ = 1176.49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24.5)-\sqrt{1176.49}}{2*-4.9}=\frac{-24.5-\sqrt{1176.49}}{-9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24.5)+\sqrt{1176.49}}{2*-4.9}=\frac{-24.5+\sqrt{1176.49}}{-9.8} $
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